Question

Factorise the following
a² - b² - c² - 2bc




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Answer 1

Answer:

α²-ɓ²+2ɓc-c² =α² - (ɓ² -2ɓc +c²)

                    =α² - (ɓ-c)²

                    =(α-(ɓ-c))(α+(ɓ-c))  [ µรเɳɠ เ∂εɳƭเƭყ α²-ɓ² =(α-ɓ)(α+ɓ) ]

 

                   = (α-ɓ+c)(α+ɓ-c)

ɦεɳcε.,α²-ɓ²+2ɓc - c²  = (α-ɓ+c)(α+ɓ-c)

Answer 2

ANSWER :-

(a + b - c) (a - b + c)

EXPLANATION :-

a² - (b² - 2bc + c²)

Using identity a² - 2ab + b² = (a-b)²

= a² - (b - c)²

Using identity a² - b² = (a + b) (a - b)

= (a + b - c) (a - (b - c))

= (a + b - c) (a - b + c)

Therefore , a²- b² + 2ab - c² = (a + b - c) (a - b + c)

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