Question

Factorise the following algebraic expression by using suitable identify x²y²-64​

Answer 1

Answer:

Hey there!!

This can also be written as

( xy )^2 - ( 8 )^2

a^2 - b^2 = ( a + b ) ( a - b )

= ( xy + 8 ) ( xy - 8 )

Hope my answer helps!

Step-by-step explanation:

Answer 2

Answer:

(xy + 8)(xy - 8)

Step-by-step explanation:

To factorise (x²y² - 64),

We know that x²y² is a perfect square (of xy).

We also know that 64 is a perfect square (of 8).

Since we are subtracting a perfect square from another, the following identity can be used to simplify it further:

(a² - b²) = (a + b)(a - b)

So,

⇒ (x²y² - 64) = (xy + 8)(xy - 8)

Hope it helps!