Factorise the following algebraic expression by using suitable identity 4a²-b²+6b-9
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Answer:
by using identities
(a-b)²=a²-2ab+b²
and (a²-b²)=(a+b)(a-b)
4a²-b²+6b-9
4a²-(b²-6b+9)
(2a)²-(b²-(2)(3)(b)+3²)
(2a)²-(b-3)²
(2a-(b-3))(2a+(b-3))
(2a-b+3)(2a+b-3)
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