factorise the following algebraic expression by using suitable identity
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1
am² = am×am
49a = a×49
14am = am×14
49a = a×49
14am = am×14
Answered by
2
take a as common.
a{m^2-14m+49}
a{m-7}^2
a{m-7}{m-7}
(ma-7a)(m-7)
a{m^2-14m+49}
a{m-7}^2
a{m-7}{m-7}
(ma-7a)(m-7)
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thanq
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