factorise the following and solve.
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Hello Mate!
4a² + b² + 25c² - 4ab - 10bc + 20ca
(-2a)² + b² + (-5c)² + 2[ (-2a)(b) + (b)(-5c) + (-5c)(-2a) ]
( a + b + c )² = a² + b² + c² + 2( ab + bc + ca )
= ( - 2a + b - 5c )²
Answer : ( - 2a + b - 5c )( - 2a + b - 5c )
Hope ot helps
4a² + b² + 25c² - 4ab - 10bc + 20ca
(-2a)² + b² + (-5c)² + 2[ (-2a)(b) + (b)(-5c) + (-5c)(-2a) ]
( a + b + c )² = a² + b² + c² + 2( ab + bc + ca )
= ( - 2a + b - 5c )²
Answer : ( - 2a + b - 5c )( - 2a + b - 5c )
Hope ot helps
ShuchiRecites:
No dear
Its correct
and ur one is too correct
This question csn have more than one answer
No its not necessary. we can take 1st and last term negative or middle term negative
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hope it helps you
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