Question

Factorise the following appropriate indentities 4y²-4y+1

Answer 1

Answer:

4y²-2y-2y+1

2y(2y-1) -1(2y-1)

(2y-1) (2y-1).

Answer 2

Answer:

(2y-1)²

Step-by-step explanation:

4y²-4y+1

By splitting the middle term-

=4y²-2y-2y+1

=2y(2y-1)-1(2y-1)

=(2y-1)(2y-1)

=(2y-1)²

Using identities

=4y²-4y+1

=(2y)²-2(2y)(1)+1. [(x-y)²=x²-2xy+y²]

=(2y-1)²