Question

Factorise the following by factorisation method (class 10)

Answer 1

Step-by-step explanation:

$6 \sqrt{3} x {}^{2} + 7x = \sqrt{3} \\ 6 \sqrt{3} x {}^{2} + 7x - \sqrt{3} = 0 \\ 6 \sqrt{3}x {}^{2} + 9x - 2x - \sqrt{3} = 0 \\ 3 \sqrt{3}x(2x + \sqrt{3} ) - 1(2x + \sqrt{3} ) \\ (3 \sqrt{3} x - 1)(2x + \sqrt{3}$

Answer 2

✿question✿

$6 \sqrt{3} x ^{2} + 7x = \sqrt{3}$

$\huge\bold\red{ ♡solution }$

$6 \sqrt{3} x^{2} + 7x - \sqrt{3} \\ \\6 \sqrt{3} x^{2} + 9x - 2x - \sqrt{3}$

3✓3x(2x+✓3 ) -(2x+✓3)

(3✓3x-1) (2x+✓3)

x= 1/3√3 and x= √3/2