Math, asked by fjsrsrsurusrjsrsjjak, 5 months ago

Factorise the following by regrouping the terms.
a) 6xy-y^2+12xz-2yz
b) b^2-ab(1-a)-a^3
c) a^2-a(x+2y)+2xy
d) x^3-2x^2y+3xy^2-6y^3
e) xy(a^2+1)-a(x^2+y^2)​

Answers

Answered by Anonymous
9

Question :-

Factorise the following by regrouping the terms.

a) 6xy  - y² + 12xz - 2yz

b) b² - ab(1 - a) - a³

c) a² - a(x + 2y) + 2xy

d) x³ - 2x²y + 3xy² - 6y³

e) xy(a² + 1)-a(x² + y²)

Solution :-

a) \sf{6xy-y^2+12xz-2yz}

\sf{= y(6x-y)+2z(6x-y) }

\sf{=  (6x-y)(y+2z)}

◘ The factorised form is (6x - y)(y + 2z).

_________________

b) \sf{  b^2-ab(1-a)-a^3}

\sf{=b^2-ab+a^2b-a^3  }

\sf{=b(b-a)+a^2(b-a)}

\sf{=(b-a)(b+a^2)}

◘ The factorised form is (b - a)(b + a²).

_________________

c) \sf{a^2-a(x+2y)+2xy}

\sf{=a^2-ax-2ay+2xy }

\sf{= a(a-x)-2y(a-x)}

\sf{= (a-x)(a-2y)}

◘ The factorised form is (a - x)(a - 2y).

_________________

d) \sf{x^3-2x^2y+3xy^2-6y^3}

\sf{=x^2(x-2y)+3y^2(x-2y) }

\sf{= (x-2y)(x^2+3y^2)}

◘ The factorised form is (x - 2y)(x² + 3y²).

_________________

e) \sf{xy(a^2+1)-a(x^2+y^2)}

\sf{= a^2xy+xy-ax^2-ay^2}

\sf{=a^2xy - ax^2 + xy - ay^2}

\sf{=ax(ay-x)-y(ay-x)}

\sf{=( ax - y )( ay - x )}

◘ The factorised form is (ax - y)(ay - x).

Answered by MissLuxuRiant
2

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