Question

factorise the following by splitting the middle term 2 root 2 X square + 9 X + 5 root 2​

Answer 1

$2 \sqrt{2} {x}^{2} + 9x + 5 \sqrt{2} \\ = 2 \sqrt{2} {x}^{2} + 4x + 5x + 5 \sqrt{2} \\ = 2 \sqrt{2} x( x + \sqrt{2} ) + 5(x + \sqrt{2} ) \\ = (2 \sqrt{2} x + 5)(x + \sqrt{2} )$

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Answer 2

Answer:

2√2x² + 9x + 5√2 = (x + √2) (2√2x + 5).

Given:

2√2x² + 9x + 5√2

To Find:

Factorization.

Step-by-step explanation:

it is given that,

2√2x² + 9x + 5√2

First multiply,

2√2 × 5√2 = 20

Now,

write b as sum of multiple of 20 i.e.

9x = 4x + 5x

we will get,

2√2x² + 4x + 5x + 5√2

⇒ 2√2x(x + √2) + 5(x + √2)

⇒ (x + √2) (2√2x + 5)

2√2x² + 9x + 5√2 = (x + √2) (2√2x + 5)

Hence, 2√2x² + 9x + 5√2 = (x + √2) (2√2x + 5).

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