Math, asked by prakasharora643, 10 months ago

Factorise the following by splitting the
middle term. 2b² + 32b + 128
$please \: help \: me \: immediately \:$

Answers

Answered by mohitgurjar5935

Answer:

$\huge\mathcal{\purple{answer}}$

By using middle term splitting;

$= 2 {b}^{2} + 32b + 128$

$= 2 {b}^{2} + 16b + 16b + 128$

$= 2b(b + 8) + 16(b + 8)$

$= (b + 8)(2b + 16)$

$=> b + 8 = 0 \: \: \: \: 2b + 16 = 0$

$=> b = - 8 \: \: \: b = - 8$

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