Math, asked by deependerparjapati, 6 months ago

factorise the following by splitting the middle term 7 under root 2 x square - 10 x - 4 under root 2​

Answers

Answered by ItzAditt007
0

AnswEr:-

Your Answer Is  \bf ( 7 \sqrt{2} - 4)(x -  \sqrt{2}).

ExplanaTion:-

Given Expression:-

  • 7\sqrt{2} - 10x - 4\sqrt{2}.

And we have to factorize the above term.

So Here,

↦ Cofficient of x² × Constant term,

 \tt = 7 \sqrt{2}  \times 4 \sqrt{2}

  \tt= 7 \times 4 \times 2.

 \tt  = 28 \times 2 = 56.

Also,

↦ 56 = 2 × 2 × 2 × 7.

And,

↦ (7 × 2) - (2 × 2) = 10 = Middle term.

So lets split the term:-

\tt\mapsto7 \sqrt{2}  {x}^{2}  - 10x - 4 \sqrt{2} .

 \tt = 7 \sqrt{2}  {x}^{2}  - (14 - 4)x - 4 \sqrt{2} .

 \tt = 7 \sqrt{2} {x}^{2}   - 14x + 4x - 4 \sqrt{2} .

  \tt = 7 \sqrt{2}x(x -  \sqrt{2}) + 4(x -  \sqrt{2})  .

 \tt =( 7 \sqrt{2} - 4)(x -  \sqrt{2}).

...Hence Factorized...

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