Question

Factorise the following by splitting the middle term please send fast thank you

Answer 1

Answer:

1)

p²-17p-60

here

a=1

b=-17

c=-60

P=AC (product=a×c)

S=B (sum= b)

p²+3p-20p-60

p(p-3)-20(p-3)

=(p-20)(p-3)

2)

b²+4b-77

here

a=1

b=4

c=-77

P=AC (product=a×c)

S=B (sum= b)

b²+11b-7b-77

b(b+11)-7(b+11)

=(b-7)(b+11)

3)

q²+7q+12

here

a=1

b=7

c=12

P=AC (product=a×c)

S=B (sum= b)

q²+4q+3q+12

q(q+4)+3(q+4)

=(q+3)(q+4)

4)

z²-13z-30

here

a=1

b=-13

c=-30

P=AC (product=a×c)

S=B (sum= b)

z²-15z+2z-30

z(z-15)+2(z-15)

=(z+2)(z-15)

5)

a²-16a-80

here

a=1

b=-16

c=-80

P=AC (product=a×c)

S=B (sum= b)

a²-20a+4a-80

a(a-20)+4(a-20)

=(a+4)(a-20)

6)

3a²+9a+6

here

a=3

b=9

c=6

P=AC (product=a×c)

S=B (sum= b)

3(a²+3a+2)

3(a²+2a+a+2)

3(a{a+2}+a+2)

=3(a+1)(a+2)