Question

factorise the following by taking out the common factor. friends please give me right answer if you right answer then I mark as brainlist​

Answer 1

Ans:- 3x²(y²+4) - 2y²(y²+4)

⁴ = 3x²y² + 12x² - 2y⁴ - 8y²

= 3x²y² - 2y⁴+12x² - 8y²

= y²(3x² - 2y²) + 4(3x² - 2y²)

= ((√3x)² - (√2y)²) (y² + 4)

= (√3x-√2y)(√3x+√2y)(y² + 4)

2. 5y³(x²-5) - 2y²(x²-5) + 3y(x²-5)

let (x²-5) = z

= 5zy³ - 2zy² + 3zy

= zy(5y²-2y + 3)

= (x²-5)y(5y²-2y+3)

= (yx² - 5y)(5y²-2y+3)

3. x²y(x-z) + y²x(z-x)

= yx³-yzx² + xzy²- y²x²

= yx³-y²x² - yzx² + xzy²

= yx²(x-y) - yzx(x - y)

= (x - y)(yx² - yzx)

= xy(x - y)(x - z)

here is your answer

hope it will help you