Factorise the following by using a suitable identity: a. a3+b3+8c3+6abc
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Using identity, a^3 +b^3 +c^3 - 3abc = (a+b+c)(a^2 + b^2 + c^2 - ab - bc - ac)
therefore,
= [a+b+c][a^2 + b^2 + (2c)^2 - ab - 2cb - 2ca]
so here u go!
pls l
Answered by
1
Step-by-step explanation:
looks like question is wrong ad there must be a -8c3 or -6abc ... please check the question
monika7845:
My ques is correct
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