Question

factorise the following equation..​

Answer 1

Given

x² - 4√3x + 9 = 0

Factories it

Solution

→ x² - 4√3x + 9 = 0

★ Solve this by splitting middle term

→ x² - 3√3x + √3x + 9 = 0

→ x(x - 3√3) + √3(x + 3√3) = 0

→ (x - 3√3)(x + √3) = 0

Either

→ (x - 3√3) = 0

→ x = 3√3

Or

→ (x + √3) = 0

→ x = -√3

Hence, 3√3 and -√3 are the zeros of given equation

Some identities

• (a + b)² = a² + b² + 2ab
• (a - b)² = a² + b² - 2ab
• a² - b² = (a + b)(a - b)