factorise the following equation: (3a-b)^2-9c^2
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Answered by
25
(3a-b)^2 - 9c^2
=> (3a-b)^2 - (3c)^2
= (3a-b+3c)(3a-b-3c)
=> (3a-b)^2 - (3c)^2
= (3a-b+3c)(3a-b-3c)
Answered by
15
hii!!
here's ur answer...
(3a-b)²-9c²
in (3a-b)² we will use the second identity which is (a-b)² = a²-2ab+b²
a=3a, b=b
= [(3a)²-2(3a)(b)+(b)²]-9c²
= 9a²-6ab+b²-9c²
hope this helps..!
here's ur answer...
(3a-b)²-9c²
in (3a-b)² we will use the second identity which is (a-b)² = a²-2ab+b²
a=3a, b=b
= [(3a)²-2(3a)(b)+(b)²]-9c²
= 9a²-6ab+b²-9c²
hope this helps..!
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