Question

factorise the following equation:
${9x }^{2} - 6x + 1$

Answer 1

$9x^2 -6x + 1$

$9x^2 -(3+3)x + 1$

$9x^2 -3x -3x + 1$

$3x(3x - 1) - 1(3x -1)$

(3x-1) (3x-1)

(3x-1)²



                               Or


9x² -6x + 1 

(3x)² -2(3×x) + 1²
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By Formula,

(a -b)² = a² + b² -2ab
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(3x -1)²






i hope this will help you


-by ABHAY

Answer 2

Hiii friend,

9X²-6X+1

=> 9X²-3X-3X+1

=> 3X(3X-1) -1(3X-1)

=> (3X-1) (3X-1)

=> (3X-1) = 0

=> 3X = 1

=> X = 1/3.

Hence,

1/3 and 1/3 are the two zeros of the POLYNOMIAL 9X²-6X+1.

HOPE IT WILL HELP YOU...... :-)