Factorise the following experience:4m*2+44m+121
Answers
Answer:
Step by Step Solution
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STEP
1
:
Equation at the end of step 1
(22m2 - 44m) + 121
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring 4m2-44m+121
The first term is, 4m2 its coefficient is 4 .
The middle term is, -44m its coefficient is -44 .
The last term, "the constant", is +121
Step-1 : Multiply the coefficient of the first term by the constant 4 • 121 = 484
Step-2 : Find two factors of 484 whose sum equals the coefficient of the middle term, which is -44 .
-484 + -1 = -485
-242 + -2 = -244
-121 + -4 = -125
-44 + -11 = -55
-22 + -22 = -44 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -22 and -22
4m2 - 22m - 22m - 121
Step-4 : Add up the first 2 terms, pulling out like factors :
2m • (2m-11)
Add up the last 2 terms, pulling out common factors :
11 • (2m-11)
Step-5 : Add up the four terms of step 4 :
(2m-11) • (2m-11)
Which is the desired factorization
Multiplying Exponential Expressions:
2.2 Multiply (2m-11) by (2m-11)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (2m-11) and the exponents are :
1 , as (2m-11) is the same number as (2m-11)1
and 1 , as (2m-11) is the same number as (2m-11)1
The product is therefore, (2m-11)(1+1) = (2m-11)2
Final result :
(2m - 11)2
Step-by-step explanation:
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