Factorise the following expression 121 square + 110 AB + 25 b square
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I think there must be 121a square.
Then itz answer would be :-
(11a+5b)square which means=
(11a+5b)(11a+5b)
Answered by
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Answer:
(121)^2 + 110ab +(25)^2
according to this formula (a + b)^2=a^2 + b^2 +2ab)
a=(121)^2=11
b=(25)^2=5
(11+5)^2 = (11+5) (11+5)
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