Factorise the following expression-
14a^2 + 11ab - 15b^2
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Answers
Answered by
45
Product of the first and the third terms = – 210a2b2
Therefore it can be write as 21ab – 10ab
Hence, 14a2 + 11ab – 15b2
= 14a2 – 21ab – 10ab – 15b2
=7a(2a +3b) – 5b(2a +3b)
=(2a +3b)(7a – 5b)
Therefore it can be write as 21ab – 10ab
Hence, 14a2 + 11ab – 15b2
= 14a2 – 21ab – 10ab – 15b2
=7a(2a +3b) – 5b(2a +3b)
=(2a +3b)(7a – 5b)
Faiqa93:
Sorry your answer is wrong
Answered by
12
the above answer is correct
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