Factorise the following expression.
63a2
– 112b2
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Answer:
63a²- 112b²
taking 7 common, we get:-
7(9a² - 16b²)
(7) [(3a)²- (4b)²]
(∵a²-b² = (a-b) (a+b)
⇒ (7) (3a-4b) (3a+4b) ans.
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