Question

factorise the following expression 6a^2-13ab+2b^2​

Answer 1

Answer:

$(6a-b)(a-2b)$

Step-by-step explanation:

Given expression: $6a^2 -13ab +2b^2$

Here sum= -13 and product =6*2=12

$-13 = -12 -1$

and $-12*-1 = 12$

So by splitting the middle term, we get

$6a^2 - 12ab- ab +2b^2 = 0$

Taking common factors out,

$6a (a-2b) -b(a-2b) =0$

Therefore, we obtain $(6a-b)(a-2b)$

Answer 2

Answer:

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