factorise the following expression.
ax²y+bxy²+cxyz
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Answer:
We have, ax
2
y=a×x×x×y
bxy
2
=b×x×y×y
and, cxyz=c×x×y×z
The three terms have x and y as common factors
∴ax
2
y+bxy
2
+cxyz=(a×x×x×y)+(b×x×y×y)+(c×x×y×z)
=x×y×(a×x+b×y+c×z)
=xy(ax+by+cz)
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