Question

factorise the following expression:
i) 63a² - 112b²​

Answer 1

Answer:

63a²- 112b²

taking 7 common, we get:-

7(9a² - 16b²)

(7) [(3a)²- (4b)²]

[∵a²-b² = (a-b) (a+b) ]

⇒ (7) (3a-4b) (3a+4b) ans.