factorise the following expression using algebraic identities
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Answered by
10
Answer:
64a^2-9b^2+42bc-49c^2
64a^2-[(3b)^2+(7c)^2-(2*3b*7c)]
(8a)^2 - ( 3b+7c)^2
[8a+(3b+7c)][8a-(3b+7c)]
(8a+3b+7c)(8a-3b-7c)
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Answered by
3
Answer:
(8a-3b-7c)*2
Step-by-step explanation:
64a*2-9b*2+42bc-49c*2
=(a)*2-(b)*2+2×b×c-(c)*2
=(8a)*2-(3b)*2+2×3a×7c-(7c)*2
=(8a-3b-7c)*2
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