Question

factorise the following expression using suitable identities 8y² + 32y + 24​

Answer 1

Answer:

✭ 8[ (y + 1) (y + 3)] ✭

Step-by-step explanation:

We will solve this factorise this term by splitting method i.e, splitting the middle term.

Let's see how...

• When a trinomial is of the form ax² + bx + c ( or a + bx + cx² ) split b (the coefficient of x in the middle term) into two parts such that the sum of these two part is equal to b and the product of these two parts is equal to product of a and c, then factorise by the grouping method.
• Product of the two parts' constant term = Product of constant 1st term and 3rd term
• Sum of 2nd part = middle term

Factorise:

➥ 8y² + 32y + 24

• When each term of the given expression contains some common factor, divide each term of the expression by that common factor and enclose the quotient within the brackets keeping the common factor outside the bracket.

➥ 8(y² + 4y + 3)

• Split 4, the coefficient of y in the middle term into two parts such that the sum of these two part is equal to 4.
• The product of these two parts is equal to product of 3 and 1.

➥ 8(y² + 3y + 1y + 3)

• Factorise by the grouping method.

➥ 8[ y(y + 3) + 1(y + 3)]

➥ 8[ (y + 1) (y + 3)]

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