factorise the following expression (X+y)(2x+3y)-(X+y)(X+1)
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(X+y)(2x+3y)-(X+y)(X+1) =0
(X+y){(2x+3y)-(X+1)} =0
(2x+3y)-(X+1) =0
2x+3y = X+1
2x-X = 1-3y
X = 1-3y
X-3y = 1
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