Question

factorise the following expression
x²yz + xy²z + xyz²​

Answer 1

Answer:

Step-by-step explanation:

Given the following expression: xyz+x′y+xyz′ where (′) means complement, I tried to simplify it by first factoring out a y so I would get y(xz+x′+xz′).

At this point, it appears I have several options:

A) Use two successive rounds of distributive property:

y((x+x′)(z+x′)+xz′))=y(z+x′+xz′)=y(z+(x′+x)(x′+z′))=y(z+x′+z′)=y(x′)=yx′

B) Or I could use absorption,

y(xz+xz′+x′)=y(x(z+z′)+x′)=y(x+x′)=y(1)=y

Answer 2

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$\sf x^{2}yz + xy²z + xyz² \\ \sf \to xyz(x+y+z)$