Question

Factorise the following expressions
1. (x + y) (2x + 3y) - (x + y (x+1)
3. x'ja - 2b) + xfa-2b)
5. 3a (p-20) - (0-20)
7. 1 + x + xy + xy
9. ala + b) +Ba+Bb
11. a + 2a + ab + 2b
2 x (6x-sn-12M8r-se
4. (a- +(a - b)
6. 8 (5x +971 + 12 (5x + 91
8. + xy + x2 + y2
10 +be+ac+ ab
12. ax + ay-bx - by​

Answer 1

Answer:

x²+14x+40

Step-by-step explanation:

given identity;

(x+4)(x+10)

this is in the form of

(x+a)(x+b)

we know that

(x+a)(x+b) = x²+(a+b)x+ab

substitute the values

x²+(4+10)x+4*10

=x²+14x+40

hope it helps you:)

Answer 2

Answer:

${a}^{2} - {b}^{2} - a - b$

$= ( {a}^{2} - {b}^{2}) - (a + b)$

$= ( {a}^{2} - {b}^{2}) - (a + b)$

$(a-b)(a + b) - (a + b)$

now taking

(a+b ) common

$(a + b)(a - b - 1)$