Factorise the following expressions. 1. (x + y) (2x + 3y) - (x + y) (x + 1)
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Given that:
(x+y)(2x+3y)−(x+y)(x+1)
=(x+y) [(2x+3y)−(x+1)] [ Taking (x+y) common]
=(x+y) [2x+3y−x−1]
=(x+y) [x+3y−1].
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