Question

Factorise the following expressions 3x2y3

, 10x3y2

, 6x2y2z


24p–12j​

Answer 1

Answer:

$\huge \mathbb \color{blue}{ANSWER \implies}$

3x2y2, 10x3y2, 6x2y2z

= (3 × x × x × y × y), (2 × 5 × x × x × x × y × y), (2 × 3 × x × x × y × y × z)

Common factors are x × x × y × y = x2y2

Hence, the common factor = x2y2.

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Answer 2

Answer:

x2y2

Step-by-step explanation:

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