factorise the following expressions 4 p square + 5 p q - 6 p q square
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Let us first find the HCF of all the terms of the given polynomial 4p
2
+5pq−6pq
2
by factoring the terms as follows:
4p
2
=2×2×p×p
5pq=5×p×q
6pq
2
=2×3×p×q×q
Therefore, HCF=p
Now, we factor out the HCF from each term of the polynomial 4p
2
+5pq−6pq
2
as shown below:
4p
2
+5pq−6pq
2
=p(4p+5q−6q
2
)
Hence, 4p
2
+5pq−6pq
2
=p(4p+5q−6q^2)
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