Question

factorise the following expressions 81-(x-7)^2​

Answer 1

Answer:

• verified answer

Step-by-step explanation:

The factorize form of the term is 81-(x-7)^2=(2+x)(16-x)81−(x−7)

2

=(2+x)(16−x)

Step-by-step explanation:

Given : Expression 81-(x-7)^281−(x−7)

2

To find : Factorize the term ?

Solution :

Expression 81-(x-7)^281−(x−7)

2

Re-write 81 as 81=9^281=9

2

81-(x-7)^2=9^2-(x-7)^281−(x−7)

2

=9

2

−(x−7)

2

Apply identity, a^2-b^2=(a+b)(a-b)a

2

−b

2

=(a+b)(a−b)

81-(x-7)^2=(9+x-7)(9-(x-7))81−(x−7)

2

=(9+x−7)(9−(x−7))

81-(x-7)^2=(2+x)(9-x+7)81−(x−7)

2

=(2+x)(9−x+7)

81-(x-7)^2=(2+x)(16-x)81−(x−7)

2

=(2+x)(16−x)

The factorize form of the term is 81-(x-7)^2=(2+x)(16-x)81−(x−7)

2

=(2+x)(16−x)

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