Question

Factorise the following expressions:-

i- x²-2ax-2ab+bx

ii- x³-2x²y+3xy²-6y³

iii- 16(a-b)³-24(a-b)²

iv- 2x³y²-4x²y³+
8xy
v- 6m²-12mn-4m+8n
​

Answer 1

this is answer of first expressio

(2)

Given : x3- 2x2y + 3xy2 - 6y

By taking x2 as common in the first two term and 3y2 as common in the second two term

x3 - 2x2y + 3xy2 - 6y2 = x2 ( x - 2y) + 3x2 ( x-2y)

Firi we get

x3 - 2x2y + 3xy2 - 6y3 = ( x-2y) ( x2+3y2 )