factorise the following expressions p-10p+25
Answers
Answered by
4
Heya !!
It should be p² - 10p +25.
THis is your answer.
Given Equation :-
p² - 10p + 25 =0
We have to search for two numbers a and b such that a+b = -10 and ab= 25.
By looking at the prime factors of 25...
25 = 5×5
We get a and b are 5 and 5.
As....
-5+(-5) = -10 and -5×(-5). = 25.
So......
p² - 10p + 25 = 0.
p² -5p - 5p + 25 = 0
p (p-5) - 5(p -5) = 0.
(p-5)(p-5) = 0
p-5 = 0 and p-5 = 0
p = 5 or p = 5
Hence the factors are (p-5) and (p-5) and zeroes are 5 and 5
Hope it helps
It should be p² - 10p +25.
THis is your answer.
Given Equation :-
p² - 10p + 25 =0
We have to search for two numbers a and b such that a+b = -10 and ab= 25.
By looking at the prime factors of 25...
25 = 5×5
We get a and b are 5 and 5.
As....
-5+(-5) = -10 and -5×(-5). = 25.
So......
p² - 10p + 25 = 0.
p² -5p - 5p + 25 = 0
p (p-5) - 5(p -5) = 0.
(p-5)(p-5) = 0
p-5 = 0 and p-5 = 0
p = 5 or p = 5
Hence the factors are (p-5) and (p-5) and zeroes are 5 and 5
Hope it helps
Answered by
2
Hii !!
I think this question is wrong.
Because where written is only p-10p+25.
It should be written there p square -10p+25
I think this question is wrong.
Because where written is only p-10p+25.
It should be written there p square -10p+25
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