Question

factorise the following expressions. pls send answer soon as soon urgently​

Answer 1

• Question

Factorise -

• (x + y) (2x + 3y) - (x + y) (x + 1)

• Solution

• Take out the common term outside the brackets.

• Here in the question (x + y) is common in both the terms.

$: \implies$ $\sf{(x + y) (2x + 3y) - (x + y) (x + 1)}$

$: \implies$ $\sf{(x + y)[(2x + 3y) - (x + 1)]}$

$\red{\bigstar}$ $\large\boxed{\sf{\blue{(x + y)[(2x + 3y) - (x + 1)]}}}$

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• Know More -

How to factories -

• Firstly, take out common no. out of the brackets.
• Write it outside the bracket.
• Now, write the left over no.s inside the bracket.

$\red{\bigstar}$Some useful identities -

• $\sf\green{{(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab}$

• $\sf\green{{(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab}$

• $\sf\green{(a + b)^3 = a^3 + b^3 + 3ab(a + b)}$

• $\sf\green{(a - b)^3 = a^3 - b^3 - 3ab(a - b)}$

Signs are changed on the following bases -

• (-) (-) = (+)

• (+) (+) = (+)

• (-) (+) = (-)

• (+) (-) = (-)