Question

factorise the following expressions x²y²-2xy+1​

Answer 1

x2+y2−2xy=(x−y)2  

x2+y2−2xy−1=(x−y)2−1=(x−y−1)∗(x−y+1)

We therefore have 2 factors: (x−y−1) and (x−y+1)

Answer 2

Answer:

(xy-1)^2

Step-by-step explanation:

x^2y^2 - 2xy + 1

(xy)^2 - 2(xy)(1) +1^2

by the formula of (a-b)^2

We can write it as

(xy-1)^2