factorise the following. friends please give me right answer if you right answer then I mark as brainlist
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Answer:
(2y-1)(128y^7+64y^6+32y^5+16y^4+2y+1)
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0
256y^8-1
Step-by-step explanation:
FORMULA: (a^2-b^2)= (a+b) (a-b)
where a= 16y^4 and b= 1
=(16y^4+1) (4y^2+1) (2y+1) (2y-1)
Hope it helped:)
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