Question

factorise the following(i)27y^3 - 125x^3 (ii)64x^3y^3 + 27z^3​

Answer 1

Answer:

A) 27y^3 -125x^3

= (3y)^3 -(5x) ^3

IDENTITY

=(a^3 -b^3) =(a+b)(a^2 + b^2 -ab)

=(3y+5x)(3y^2 + 5x^2 -3y *5x)

=(3y+5x)(9y^2 +25x^2 -15xy)

ANSWER

Answer 2

Answer:

1) (3y)^3-(5x)^3

2)(4xy)^3+(3z)^3

Step-by-step explanation:

1)as we know that a^3-b^3=(a-b)(a^2+ab+b^2)

so,put value

(3y-5x)(9y^2+15xy+25x^2)

and open it will give you 27y^3-125x^3

so ans is (3y)^3-(5x)^3

2)as we know that a^3+ b^3=(a+b)(a^2-ab+b^2)

then solve with this identity as i solved in 1 u will get the question and answer i gave