Question

Factorise the following.
(i) 7 a2 + 7 a – 42
(ii) y2 + 19 y – 150
(iii) 3 x2 + 48 x +117

Answer 1

Answer:

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Answer 2

i) 7a²+7a−42

7a²+7a−42

=7(a−2)(a+3)

ii) The middle number is 19 and the last number is -150.

Factoring means we want something like

(y+_)(y+_)

Which numbers go in the blanks?

We need two numbers that.

Add together to get 19

Multiply together to get -150

Can you think of the two numbers?

Try -6 and 25:

-6+25 = 19

-6*25 = -150

Fill in the blanks in

(y+_)(y+_)

with -6 and 25 to get.

(y-6)(y+25)

iii) 3x²+48x+117

3x²+48x+117

=3(x+3)(x+13)

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