Question

Factorise the following:
(i) x³-y³+1+3xy​

Answer 1

Step-by-step explanation:

a^3 + b^3 + c^3 - 3abc = (a+b+c)(a^2+b^2+c^2-ab-bc-ca)

Here a=x, b=-y, c=-1

Now,

x^3-y^3-1-3xy = (x-y-1) (x^2+y^2+1+xy-y+x)

Hope it is satisfactory :-)