Question

factorise the following identities using appropriate identities: 4x²+4xy+y²​

Answer 1

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$\huge\sf\underline\red{Question}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 4x {}^{2} + 4xy + y {}^{2}$

$\huge\sf\underline\blue{Answer}$

$\small\fbox\pink{Identity:(a+b)²=a²+b²+2ab}$

$\: \: \: \: \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 4x {}^{2} + 4xy + y {}^{2} \\ \\ = \: \: \: \: \: \: \:(2x) {}^{2} + 2(2x \times y) + (y) {}^{2}$

$\\ \\ here \: \: we \: \: have \: \: a {}^{2} as \: 2x \: \: and \: {b}^{2} as \: y$

$after \: substituting \: \: in \: \: formula \: \: we \: \: get \: as \:$

$\\ \\ \: \: \: = \: \: \: \: \: \: \: \: \: \: \: \: \: (2x + y) {}^{2} \\ \\ hence \: \: your \: \: answer \: \: is \: (2x + y) {}^{2}$

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$\small\purple{\textbf {\textsf {@akeertana503}}}$