Question

factorise the following m^2+1/m^2-23​

Answer 1

Step-by-step explanation:

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Answer 2

The required solution is $\frac{m^{2} +1}{(m-\sqrt{23})(m+\sqrt{23}) }$

Step-by-step explanation:

The Given expression is :

$\frac{m^{2} +1}{m^{2}-23 }$

We can write 23 as (√23)²

$=\frac{m^{2} +1}{m^{2}-(\sqrt{23}) ^{2} }$

Applying the Difference of Squares that is:

$a^{2} -b^{2} =(a-b)(a+b)$

$=\frac{m^{2} +1}{(m-\sqrt{23})(m+\sqrt{23}) }$

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