Question

factorise the following M square - 20 m + 68​

Answer 1

Step-by-step explanation:

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We know that, for roots α,β :

m² - (α + β)m + αβ = 0

(m-α)(m-β) = 0

Now,

α,β

= [20 ± √( 400 - 272 )]/2

= [20 ± √128]/2

= 10 ± 4√2

m² - 20m + 68

= [m - ( 10 + 4√2)]×[ m - (4√2 - 10)]