Question

Factorise the following:

P2 + 30P + 216

4x2 – 4x + 1

X2 + 4x – 77

X2 = 17x + 60

Find x2 + y2 when x – y = 13 and xy = 28.

Subtract b(b2 + b – 7) from 3b2 – 8 and find the value of the expression obtained for b = –3.

Answer 1

1.

P² + 12p+18p+ 216 = P(P + 12) + 18(P+12)

(P +12) (P+18)

2.

4x² - 4x + 1 = (2x - 1)²  or (2x-1) (2x-1)

3.

x² + 4x - 77 = x² + 7x - 11x - 77 = x(x + 7) -  11(x + 7)

(x - 11) (x +7)

4.

x² - 17x + 60 = x² - 12x - 5x + 60 = x(x -12) - 5(x -12)

(x -12) (x - 5)

ii

(x-y)² = x² + y² - 2xy

13² = x² + y² - 2*28

169 = x² + y² = 56

x² + y² = 169 + 56 = 225

iii

(3b² - 8) - [b(b² + b - 7)]

(3b² - 8) - (b³ + b² - 7b)

3b² - 8  - b³ - b² + 7b

2b² - 8 - b³ + 7b

18 - 8 + 27 - 21

= 16

Hope it helped you

Answer 2

Answer:

16 is answer dear friend