Question

factorise the following
p²q - pr² - pq + r2​

Answer 1

Answer:

(pq-r2) (p-1)

Explanation:

p2q- pr2- pq + r2

By grouping the expression

= (p2q - pq) + (r2 - pr2)

= pq (p -1) + r2 (1 - p)

= pq (p - 1) - r2 (p - 1)

= [ (1 - p) = - (p - 1) ]

= ( pq - r2) ( p - 1)

Therefore, (p - 1) is the common factor