Question

Factorise the following.. pls ans with clear steps.... need accurate answer

Answer 1

$\textbf{Solution:}$


$16(a + b ){}^{2} - 4a - 4b \\ \\ 16(a + b ){}^{2} - 4(a + b) \\ \\ (a + b)(16(a + b) - 4) \\ \\ 4(a + b)(4a + 4b - 1)$
$\textbf{Thank you!!}$

Answer 2

16(a+b)²-4a-4b
= 16(a+b)(a+b)-4(a+b)
=(a+b){16(a+b)-4}
=(a+b){16a+16b-4}
=(a+b){4(4a+4b-1)
=4(a+b)(4a+4b-1)