Question

Factorise the following polynomial. 1. (X + 2)² + 5 (x + 2)
2. (3y - 5z)³ + 7 (3y - 5z)²
3. 5 x + 10 Y - 7 (x + 2 y)²
4. (x + y)(3x ‐ 7) ‐ (x + y) (2 x -11)


ANSWER ALL THE QUESTIONS

AND PLEASE WITH SOLUTION ​

Answer 1

Answer:

1. (x+7)(x+2)

Step-by-step explanation:

1.

(x+2)^2=x^2+4x+4

then,

x^2+4x+4+5x+10

x^2+9x+14

factors of 14=7*2

so,

x^2+(7+2)x+14

x^2+7x+2x+14

take the pairs

x(x+7)+2(x+7)

(x+7)(x+2) Answer

Answer 2

Answer:

1.(x+2)^2+5(X+2)

( X^2+2^2+2×X×2) +5(x+2)

(x^2+4+4x)+5(x+2)

( x^ 2+2x+2x+4)+5(x+2)

x(x+2)+2(x+2)+5(x+2)

(x+7)(x+2)

2.(3y_5z)^3+7(3y-5z)^2

let 3y _ 5z=P

=p3-7p2

= p2(p-7)

= (3y-6z)^2 (3y-5z-7)

(3y-6z)(3y-6z)(3y-5z-7)

(3y-6z)(3y-5z-7) ans.

3.5x+10y-7(x+2y)^2

5(x+2y)-7(x+2y)^2

let . x+2y=P

5p-7p^2

p(5-7p)

(x+2y)(x+2y-2).