Question

factorise the following polynomial:
1)x^2+6x+8 ​

Answer 1

Answer:

Given that: x

2

+6x+8

=x

2

+4x+2x+8, (split middle term)

=(x

2

+4x)+(2x+8), (group pair of terms)

=x(x+4)+2(x+4), (factor each binomials)

=(x+4)(x+2), (factor out common factor (x+4)

Hence factors of x

2

+6x+8 are (x+4)(x+2)

Answer 2

$\huge\bold{\mathtt{\purple{A {\pink {N {\green {S{\blue{W {\red{E {\orange {R}}}}}}}}}}}}}$

First find 2 numbers p & q such that p+q =6 and pq=8

Now x²+6x+8 => x²+4x+2x+8

⠀⠀⠀⠀⠀⠀⠀⠀⠀=x(x+4)+2(x+4)

⠀⠀⠀⠀⠀⠀⠀⠀⠀= (x+4)(x+2)

$\huge\bf{\purple{♡♡♡♡}}$

=(x+4)(x+2)