Question

factorise the following polynomial:
1)x^2+6x+8 ​​

Answer 1

Answer

First find 2 numbers p & q such that p+q =6 and pq=8

Now x²+6x+8 => x²+4x+2x+8

⠀⠀⠀⠀⠀⠀⠀⠀⠀=x(x+4)+2(x+4)

⠀⠀⠀⠀⠀⠀⠀⠀ ⠀= (x+4)(x+2)

Answer 2

$\large \blue{Solution}$☟︎︎︎

First find 2 numbers p & q such that p+q =6 and pq=8

Now x²+6x+8 => x²+4x+2x+8

⠀⠀⠀⠀⠀⠀⠀⠀⠀=x(x+4)+2(x+4)

⠀⠀⠀⠀⠀⠀⠀⠀ ⠀=[x+4] [x+2]